每日获取变更的CVE漏洞
查看CVE推送每日更新,做成类似于新闻头条的推送是企业安全从业人员最应该掌控的能力。随着安全体系工作的开展,每位甲方安全从业者从开始的朋友圈接收漏洞信息,到各个平台接收漏洞信息,但无论是三方还是朋友圈,都不能百分之百贴合与及时的自己想要掌控的漏洞信息,也正是基于这点,我开始自己做CVE的推送工作。
首先要爬取CVE,有一个比较方便的网站,内里集成了每天发布或更新的CVE
URL:https://cassandra.cerias.purdue.edu/CVE_changes/today.html
每一个链接都会链接到CVE漏洞详情中
那我们使用python针对CVE进行信息的爬取
headers = {
‘User-Agent’:’Mozilla/5.0 (X11; Linux x86_64; rv:52.0) Gecko/20100101 Firefox/52.0′,
‘Accept’:’text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8′,
‘Accept-Language’:’zh-CN,zh;q=0.8,en-US;q=0.5,en;q=0.3′,
‘Accept-Encoding’:’gzip, deflate’,
‘Upgrade-Insecure-Requests’:’1′,
}
url = "https://cassandra.cerias.purdue.edu/CVE_changes/today.html"
def get_cve_urls():
”’获取最新的cve漏洞url地址”’
start_content = ‘New entries’ # 起始字符串
end_content = ‘Graduations’
response = requests.get(url, headers=headers, timeout=60)
response = str(response.text)
start_index = response.index(start_content)
if start_index >= 0:
start_index += len(start_content)
end_index = response.index(end_content)
cve_urls_content = response[start_index:end_index] # 获取网页的指定范围
soup = BeautifulSoup(cve_urls_content,’lxml’)
cve_url_lists = [] # 存放获取到的cve url
for u in soup.find_all(‘a’):
cve_url = u["href"]
cve_url_lists.append(cve_url)
# print(cve_url)
return cve_url_lists
def get_cve_info():
”’获取最新cve漏洞信息”’
print ‘[*] 最新cve漏洞信息:/n’
sleep(2)
cve_urls = get_cve_urls()
numid = 1
for cve_url in cve_urls:
response = requests.get(cve_url,headers=headers,timeout=60)
response = response.text
soup = BeautifulSoup(response,’lxml’)
table = soup.find("div",id="GeneratedTable").find("table") # 获取table标签内容
cve_id = table.find_all("tr")[1].find("td",nowrap="nowrap").find("h2").string # cve id
cve_description = table.find_all("tr")[3].find("td").string # cve 介绍
其中会有一部分英文的CVE介绍会存在特殊字符,比如单引号,这时我们需要将单引号做处理后才能输出
if str(cve_description).find(‘/”) != -1:
cve_description = str(cve_description).replace(‘/”, ”)
print(‘替换特殊字符处理–/”)